<pre id=code><font face=courier size=2 id=code>
&lt;%
n=0
'j=1
for i=0 to j

if n&lt;&gt;90 then
j=j+1
response.write "&lt;br&gt;j= "&j
end if
n=n+1
response.write "&lt;br&gt;n= "&n
next

'This must loop 90 times but it loops 1 time why is that ?
'anyhelp ?
%&gt;

</font id=code></pre id=code>

because you have the upper limit of your loop set to j, not n

Try this:

&lt;%
n=0
'j=1
Do While n &lt; 90
'for i=0 to j
If n&lt;&gt;90 Then
j=j+1
Response.Write "&lt;br&gt;j= " & j
End If
n=n+1
Response.Write "&lt;br&gt;n= " & n
'next
Loop
%&gt;

Doc
Rangewalk Digital Studios

Edited by - on 08 Nov 2002 04:13:54

<BLOCKQUOTE id=quote><font size=1 face="Verdana, Arial, Helvetica" id=quote>quote:<hr height=1 noshade id=quote>
because you have the upper limit of your loop set to j, not n

Try this:

&lt;%
n=0
'j=1
Do While n &lt; 90
'for i=0 to j
If n&lt;&gt;90 Then
j=j+1
Response.Write "&lt;br&gt;j= " & j
End If
n=n+1
Response.Write "&lt;br&gt;n= " & n
'next
Loop
%&gt;

Doc
Rangewalk Digital Studios

Edited by - on 08 Nov 2002 04:13:54
<hr height=1 noshade id=quote></BLOCKQUOTE id=quote></font id=quote><font face="Verdana, Arial, Helvetica" size=2 id=quote>

It should increase the upper limit of loop when it loops one time as j=j+1
but it doen not do that

i want to loop the code depending on the varibale value that is inside the loop but i am unbale to do this any one can tell em how can i loop a code depending on the variable value that is inside the loop ?
Suhailkaleem